tag:blogger.com,1999:blog-416737812331434120.post8554735225533618037..comments2022-08-02T23:10:36.652-07:00Comments on theory: Dharwadker and Khachatryan's prediction of the Higgs boson massUnknownnoreply@blogger.comBlogger4125tag:blogger.com,1999:blog-416737812331434120.post-31229340336797486082013-04-01T23:05:17.176-07:002013-04-01T23:05:17.176-07:00I still think that the proper formula is 2H=W+ + W...I still think that the proper formula is 2H=W+ + W- + Z0 + poton)/sqrt(4) or perhaps 2H=Sum (Sm boson masses).andrewhttps://www.blogger.com/profile/08172964121659914379noreply@blogger.comtag:blogger.com,1999:blog-416737812331434120.post-72889588409173098002012-02-28T12:27:59.157-08:002012-02-28T12:27:59.157-08:00Mr nothing
maybe you are interested
http://vixra...Mr nothing<br /><br />maybe you are interested<br /><br />http://vixra.org/abs/1202.0064mr nothinghttps://www.blogger.com/profile/05182750705725644070noreply@blogger.comtag:blogger.com,1999:blog-416737812331434120.post-48040290071229241712012-01-05T11:57:19.620-08:002012-01-05T11:57:19.620-08:00There is an illustration here.
2W + Z -> 2H
2...There is an illustration <a href="http://nige.wordpress.com/2012/01/05/supersymmetry-and-nambu-goldstone-bosons-composed-of-a-neutrino-condensate/" rel="nofollow">here</a>.<br /><br />2W + Z -> 2H<br /><br />2(80.4) + 91.2 = 2(126) GeV.<br /><br />Note that 2W -> H is one Standard Model Higgs production interaction, while<br /><br />truth quark + anti-truth quark -> H<br /><br />is another Standard Model Higgs production interaction. If we treat this second example as equivalent to a Bose-Einstein condensate (each quark being one fermion in the condensate boson), the Z boson is in some sense equivalent to a spin-1 version of the H spin-0 boson, so <br /><br />2W + Z -> 2H<br /><br />is feasible, although only one H boson has the spin-0 observed, and the other is spin-1 (right-handed spinor, if it doesn't participate in weak interactions, thus remaining invisible to ATLAS and CMS).Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-416737812331434120.post-46286047783380544762012-01-04T07:33:50.759-08:002012-01-04T07:33:50.759-08:00Cooper pairs of spin-1/2 fermions produce a spin-1...Cooper pairs of spin-1/2 fermions produce a spin-1 boson (condensate) explaining superconductivity, so since the Higgs spin-0 boson is already a boson, your case is that you're not going to have two Higgs fermions forming a Cooper pair.<br /><br />However, they do point out on pages 2-3:<br /><br />"Theoretically, it is known that the SM Higgs boson is one neutral quantum component of the Higgs field, along with another neutral and two charged components acting as Goldstone bosons."<br /><br />- http://arxiv.org/PS_cache/arxiv/pdf/0912/0912.5189v1.pdf<br /><br />What they are really doing (so far as their prediction is valid, ignoring BS arm-waving) is replacing this SM Higgs mechanism with a ~126 GeV spin-0 Higgs boson formed from two half integer spin particles (fermions).<br /><br />While "supersymmetry" (postulating an additional high mass boson for every fermion in order to try to achieve similar couplings for all interactions at the Planck scale) is arm-waving unfalsifiable speculation, there is a glimmer of relevant physics you can gain here, if you go for a simpler and more predictive "supersymmetry" in which all bosons are composites of either massless or massive fermions.<br /><br />Hence, SU(2) can be thought of as having two different charges of spin-1/2 fermions and their antiparticles, which can combine in 2x2 = 4 ways producing three distinctive bosons, with electric charges +1, -1, and 0 (there are two ways you get zero electric charge, thus a total of only three kinds of bosons from two charges of fermions).<br /><br />Please see page 51 of Woit's 2002 paper "QFT an representation theory" (part 10, Speculative remarks about the standard model) at http://arxiv.org/PS_cache/hep-th/pdf/0206/0206135v1.pdf where he shows that taking U(2) as a subset of SO(4) gives the standard model electroweak fermions with chiral features, for both leptons and quarks if the hypercharge is selected to make the "overall average U(1) charge of a generation of leptons and quarks to be zero."<br /><br />This is the underlying physics of the so-called "Higgs boson" mass (mass is quantum gravitational charge, and the "Higgs mechanism" ignores this), because since 1996 we have been publishing and a predictive U(1) gauge gravity theory, and the charge of quantum gravity is mass: so Woit's 2002 argument about averaging hypercharge should also apply to masses for the particles. If there are right and left handed weak gauge bosons, half of the mass (the right-handed spinors) is "dark matter" because of the short-range (due to the mass) and the fact that it doesn't undergo weak interactions. So Woit's 2002 argument of averaging charges, applied to gravitational charges (masses) of the weak bosons, with only half of them engaging in weak interactions, could substantiate the formula (80.4 + 80.4 + 90)/2 ~ 126 GeV.Anonymousnoreply@blogger.com