_{H}= 1/2 (m

_{W+}+ m

_{W-}+ m

_{Z}) ... and for anyone impressed by the result, it might be tempting to appropriate the formula, but try to justify it on some other basis.

However, that's not enough for snarxiv blog. I don't want to leave this stone unturned. So I'm going to be drilling down into the "logic" of the paper, trying to unearth the quasi-deductive process whereby this formula is supposed to follow from Ashay Dharwadker's rather unusual construction. Let's start with what must be the final step in the logic - found on pages 55 and 56:

Since the Higgs particle/antiparticle will be identified (as a Cooper pair), their combined energy would then be the sum of the masses of all other bosons defined on the particle frame. We can have all types of bosons superposed on a single particle frame, and the single Cooper pair of the Higgs particle/antiparticle must be able to attribute energy/rest mass to all types of bosons on this particle frame, by the Higgs-Kibble mechanism. The particle frames of the bosons can be superposed at a point in space-time because they follow the Bose-Einstein statistics. Hence, this Cooper pair must have at least enough energy to attribute the sum of the rest masses of all types of bosons defined on the particle frame. On the other hand, the most important property of Bose condensation is that the Cooper pair of the Higgs particle/antiparticle must have minimum energy, so it can have at most the energy required to attribute the sum of the rest masses of all types of bosons defined on the particle frame. This must be the lowest energy state possible for the Higgs boson when it undergoes Bose condensation.

The "particle frame" is a type of disk structure, illustrated many times in the paper, and all the standard model particles are associated with regions of this disk.

It appears that the logic is as follows: The Higgs boson provides the mass for everything. For some reason, we will suppose that it delivers this mass in the form of a "Cooper pair" made of a Higgs particle and a Higgs antiparticle. The energy must be enough to provide the masses of all the massive bosons. But the energy of the Cooper pair will be a minimum. Therefore "masses of all the massive bosons" = "mass of Higgs particle + mass of Higgs antiparticle" and you get the formula.

The logic is illogical because Cooper pairs don't play a role in the Higgs mechanism, Bose condensation is irrelevant when we are comparing different species of boson, and probably for other reasons too. And that's not even addressing the rest of the theoretical framework, starting with Dharwadker's almost certainly wrong proof of the four-color theorem, which employs the Steiner system S(5,8,24). The symmetry group of S(5,8,24) is the exceptional group M

_{24}, a subgroup of the permutation group S

_{24}, and it appears that types of particle are associated with permutations, possibly elements of M

_{24}. But M

_{24}has about a quarter of a billion elements, so either we're talking about certain special elements, or some very large equivalence classes...

Anyway, I don't know when I'll return to this. Mostly I just wanted to begin to understand how the paper is supposed to work. Usually the theme of this blog is about trying to find more sense than expected in a crazy idea. Here I'm instead analyzing the logic of a paper, ultimately in order to show its flaws - but also just to bring into the open how it's supposed to work. So perhaps this post will help other readers of the paper who want to understand where the prediction comes from, but who are lost among its peculiarities.

I should add that I was driven to look again at the paper by the always interesting Marni Sheppeard, who is taking it seriously.

Cooper pairs of spin-1/2 fermions produce a spin-1 boson (condensate) explaining superconductivity, so since the Higgs spin-0 boson is already a boson, your case is that you're not going to have two Higgs fermions forming a Cooper pair.

ReplyDeleteHowever, they do point out on pages 2-3:

"Theoretically, it is known that the SM Higgs boson is one neutral quantum component of the Higgs field, along with another neutral and two charged components acting as Goldstone bosons."

- http://arxiv.org/PS_cache/arxiv/pdf/0912/0912.5189v1.pdf

What they are really doing (so far as their prediction is valid, ignoring BS arm-waving) is replacing this SM Higgs mechanism with a ~126 GeV spin-0 Higgs boson formed from two half integer spin particles (fermions).

While "supersymmetry" (postulating an additional high mass boson for every fermion in order to try to achieve similar couplings for all interactions at the Planck scale) is arm-waving unfalsifiable speculation, there is a glimmer of relevant physics you can gain here, if you go for a simpler and more predictive "supersymmetry" in which all bosons are composites of either massless or massive fermions.

Hence, SU(2) can be thought of as having two different charges of spin-1/2 fermions and their antiparticles, which can combine in 2x2 = 4 ways producing three distinctive bosons, with electric charges +1, -1, and 0 (there are two ways you get zero electric charge, thus a total of only three kinds of bosons from two charges of fermions).

Please see page 51 of Woit's 2002 paper "QFT an representation theory" (part 10, Speculative remarks about the standard model) at http://arxiv.org/PS_cache/hep-th/pdf/0206/0206135v1.pdf where he shows that taking U(2) as a subset of SO(4) gives the standard model electroweak fermions with chiral features, for both leptons and quarks if the hypercharge is selected to make the "overall average U(1) charge of a generation of leptons and quarks to be zero."

This is the underlying physics of the so-called "Higgs boson" mass (mass is quantum gravitational charge, and the "Higgs mechanism" ignores this), because since 1996 we have been publishing and a predictive U(1) gauge gravity theory, and the charge of quantum gravity is mass: so Woit's 2002 argument about averaging hypercharge should also apply to masses for the particles. If there are right and left handed weak gauge bosons, half of the mass (the right-handed spinors) is "dark matter" because of the short-range (due to the mass) and the fact that it doesn't undergo weak interactions. So Woit's 2002 argument of averaging charges, applied to gravitational charges (masses) of the weak bosons, with only half of them engaging in weak interactions, could substantiate the formula (80.4 + 80.4 + 90)/2 ~ 126 GeV.

There is an illustration here.

ReplyDelete2W + Z -> 2H

2(80.4) + 91.2 = 2(126) GeV.

Note that 2W -> H is one Standard Model Higgs production interaction, while

truth quark + anti-truth quark -> H

is another Standard Model Higgs production interaction. If we treat this second example as equivalent to a Bose-Einstein condensate (each quark being one fermion in the condensate boson), the Z boson is in some sense equivalent to a spin-1 version of the H spin-0 boson, so

2W + Z -> 2H

is feasible, although only one H boson has the spin-0 observed, and the other is spin-1 (right-handed spinor, if it doesn't participate in weak interactions, thus remaining invisible to ATLAS and CMS).

Mr nothing

ReplyDeletemaybe you are interested

http://vixra.org/abs/1202.0064

I still think that the proper formula is 2H=W+ + W- + Z0 + poton)/sqrt(4) or perhaps 2H=Sum (Sm boson masses).

ReplyDelete